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PERCENTAGES Basics and Problem Solving


   Percentages in the Aptitude 



        Students, Here  I have  explained some of  the  Example     problems and the basics up on the Problems.





Basics 


The Parts according to equal to 100 we calculated their Percent in 100
as

1=100%

1/2=50%

1/3=331/3%

1/4=25%

1/5=20%

1/6=16  2/3%

1/7=14.28%

1/9=12.50%

1/10=10%

1/11=9 1/11%

1/12=8 1/3%

2/3=66  2/3 %

5/4=  5+1/4=125%

3/5=3 1/5=60%


Examples of the Percentages Problems


1)  60% of a Number is 48

A)   60/100*x=48
   
        x=480/6

         x = 80

2)  when a number is increased by 20% it gives 720 then find the Original Number

A)  given as 20% increased so,

      100% + 20% ----> 720

      100%   ----->   ?

     100/120*720=600


3) when  a  number is decreased by 30% it gives 1234, find the number when it is increased by 40%?

A) suppose we take 100 as a original number

    Decreased is 30% so,
  
      100%-30%=70%---> 1234

     100%+40%----> ?


      140/70* 1234= 2468 ( Getting Answer by calculated as follows)


4)     A Student secured 45% of marks to pass the exam  student got 167 marks and got failed by 13 marks ? Find Maximum Marks?

A)    45%  of  marks student is failed by 13 Marks  So,

         45% ----> 167+13 Marks=180

         100% -----> ?

       180/45*180 = 400 Marks (Maximum Marks ) 
           













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