PERCENTAGES Basics and Problem Solving
Percentages in the Aptitude
Students, Here I have explained some of the Example problems and the basics up on the Problems.
Basics
The Parts according to equal to 100 we calculated their Percent in 100
as
1=100%
1/2=50%
1/3=331/3%
1/4=25%
1/5=20%
1/6=16 2/3%
1/7=14.28%
1/9=12.50%
1/10=10%
1/11=9 1/11%
1/12=8 1/3%
2/3=66 2/3 %
5/4= 5+1/4=125%
3/5=3 1/5=60%
1/2=50%
1/3=331/3%
1/4=25%
1/5=20%
1/6=16 2/3%
1/7=14.28%
1/9=12.50%
1/10=10%
1/11=9 1/11%
1/12=8 1/3%
2/3=66 2/3 %
5/4= 5+1/4=125%
3/5=3 1/5=60%
Examples of the Percentages Problems
1) 60% of a Number is 48
A) 60/100*x=48
x=480/6
x = 80
2) when a number is increased by 20% it gives 720 then find the Original Number
A) given as 20% increased so,
100% + 20% ----> 720
100% -----> ?
100/120*720=600
3) when a number is decreased by 30% it gives 1234, find the number when it is increased by 40%?
A) suppose we take 100 as a original number
Decreased is 30% so,
100%-30%=70%---> 1234
100%+40%----> ?
140/70* 1234= 2468 ( Getting Answer by calculated as follows)
4) A Student secured 45% of marks to pass the exam student got 167 marks and got failed by 13 marks ? Find Maximum Marks?
A) 45% of marks student is failed by 13 Marks So,
45% ----> 167+13 Marks=180
100% -----> ?
180/45*180 = 400 Marks (Maximum Marks )
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