WE PROVIDE ALL

Showing posts with label Aptitude. Show all posts
Showing posts with label Aptitude. Show all posts

SimpleInterest Basics and Problem Solving


SimpleInterest Basics and Problem Solving

Simple Interest  Basics and the Problem Solving mechanisms are mentioned below. All Students who are preparing for the Govt Exams or Any other exams it will be helpful.

About Simple-Interest Basics and problem Solving :

Formula:

Simple Interest (S.I)=  PTR/100;

where  P= Principle , T=Time ,  R= Rate Of Intrest   these are the terms used in the problem solving mechanisms



  • I=PTR/100,



  • P=100*I/TR



  • T=100*I/PR



  • R= 100*I/PT


1)   Find the simple Interest on 6,000 for 4 years at 15%  Per Anum ?

A)   our Formula is I=PTR/100,

          I=6,000*4*15/100;

          I=3,600.


 2)   On what sum of money will the Simple-Interest  be 2,000 in  5 Years at 8% per Annum?


A)   Interest is 2,000  time= 5 years  Rate of Interest = 8%

       I=TR%

       I=5*8%;
   
       I= 40%

 for 40 %---------> 2,000
     
        100%--------->  ?

      100/40 * 2,000= 5,000(Answer)


3)  The Simple Interest on 6,400 at 12 1/2%  per Ann um Interest is 2,000 Find the Period?

A)  Principal =6,400

      Rate of Interest is 25/2;

      I=2,000

    TR%=1* 25/2;

    6,400 * 25/2* 100 = 800


    1 Year = 800

    ? years------> 2,000    =>   2,000/800= 5/2 (2.5 years)


4)  What sum will amount of Rs 1920/- in 4 Years at  15% per Annum ?

A)  Principle  =?;

      Amount=1,920     Time = 4 Years  Rate of Interest = 15%  A=Principle+ Interest


    Amount = 100 % + 60 %

    160% -------> 1,920

   100%----------> ?


  100/160 * 1,920  = 1200 (Answer)

















     


PERCENTAGES Basics and Problem Solving


   Percentages in the Aptitude 



        Students, Here  I have  explained some of  the  Example     problems and the basics up on the Problems.





Basics 


The Parts according to equal to 100 we calculated their Percent in 100
as

1=100%

1/2=50%

1/3=331/3%

1/4=25%

1/5=20%

1/6=16  2/3%

1/7=14.28%

1/9=12.50%

1/10=10%

1/11=9 1/11%

1/12=8 1/3%

2/3=66  2/3 %

5/4=  5+1/4=125%

3/5=3 1/5=60%


Examples of the Percentages Problems


1)  60% of a Number is 48

A)   60/100*x=48
   
        x=480/6

         x = 80

2)  when a number is increased by 20% it gives 720 then find the Original Number

A)  given as 20% increased so,

      100% + 20% ----> 720

      100%   ----->   ?

     100/120*720=600


3) when  a  number is decreased by 30% it gives 1234, find the number when it is increased by 40%?

A) suppose we take 100 as a original number

    Decreased is 30% so,
  
      100%-30%=70%---> 1234

     100%+40%----> ?


      140/70* 1234= 2468 ( Getting Answer by calculated as follows)


4)     A Student secured 45% of marks to pass the exam  student got 167 marks and got failed by 13 marks ? Find Maximum Marks?

A)    45%  of  marks student is failed by 13 Marks  So,

         45% ----> 167+13 Marks=180

         100% -----> ?

       180/45*180 = 400 Marks (Maximum Marks )